Before starting this lesson, determine if your students need to work through the Pythagorean Review activity. Some things to consider:
- Are students comfortable with the Pythagorean theorem?
- Do students recognize the Pythagorean theorem as a geometric relationship among the areas of squares on the sides of a right triangle?
If your students do not possess sufficient understanding of the Pythagorean theorem, have them work on the Pythagorean Review activity sheet. In tandem with the activity sheet, they can investigate the Pythagorean theorem using the Pythagorean Review applet. If students have Internet access at home, you could assign this as independent work to be done before proceeding with this lesson. Students should complete the Pythagorean Review activity sheet individually.
To proceed with this lesson, distribute the Squares on a Triangle activity sheet.
This activity sheet must be completed using a computer that has Internet access, since it involves accessing the Squares on a Triangle applet. In a computer lab setting, pair students so that they cay work on the activity sheet together. Have one student read the activity sheet while the other manipulates the applet. Partners may switch roles after Question 5.
If students are not used to doing this type of discovery learning, encourage their creativity. Tell them that you are looking for their thoughts and intuitions and not so much concerned that they get the right answer the first time through.
Selected Answers to the Squares on a Triangle Activity Sheet
1. Answers will vary, but Area Square I + Area Square II should be larger than Area Square III for acute triangle, and smaller for obtuse triangles.
(Students may have difficulty understanding what exactly is meant by "compare," so for students are having difficulty getting started, simply asking, "Is one bigger than the other?" may suffice.)
2. In an acute triangle, a2 + b2 will be greater than c2.
In an obtuse triangle, a2 + b2 will be less than c2.
6. For acute triangles, students should realize that ASquare I + ASquare II – ADefect I – ADefect II = ASquare III.
For obtuse triangles, students should realize that ASquare I + ASquare II + ADefect I + ADefect II = ASquare III.
(If students are struggling at this point, remind them that they are attempting to find some combination of the areas of Square I, Square II, Defect I, and Defect II that will equal the area of Square III.
For the acute triangle, as a further hint, point out that the defects overlap the squares on each side. Also, since in acute triangles, the sum of the square areas on the smaller two sides is larger than the area of the square on the largest side, the defects need to be subtracted from the total combination in order to make it equal to the area of Square III.
For the obtuse triangle, notice that the defects do not overlap the squares on each side this time; hence, the defect areas needed to be added to the areas of Squares I and II.)
Depending upon the progess of the students, Questions 7 through 9 might be more appropriate for a guided class discussion, leaving Questions 10 through 13 as individual or partner work.
7. Since the area of a rectangle is length times width, the area is a · x.
8. x = b cos C
(Students struggling at this point should have the right triangle containing sides x and b, as well as ∠C.)
9. and 10. Area = a · x = ab cos C.
12. The area of Square III equals the areas of Square I and Square II minus the areas of Defect I and Defect II.
13. c2 = a2 + b2 – 2ab cos C.