
Ask students to tell their classmates about the tallest place they've ever been. If students remember, have them list the height above sea level of those locations, and ask them to describe what they saw from that height. In most cases, students will be able to describe how far they were able to see to the horizon. For reference, research the height above sea level of your current location, as well as the height above sea level of a few nearby attractions. If there is a well-known mountain nearby, find out the height of its summit. Should students have difficulty remembering details about places they've been, use the data about nearby locations to give students a sense of height above sea level.
Now ask students to imagine what it would be like to stand on the top of Mount Everest, which is 29,035 feet above sea level. Ask them, "How far do you think you'd be able to see to the horizon if you were standing at the summit of Mount Everest?" Allow students to speculate, but do not offer opinions about their estimates. Explain that the focus of this lesson is for them to attempt to answer that question.
Distribute the first page of the Top of the World activity sheet. Inform students that they should answer questions 1 and 2 fairly quickly; at this point, their guess should be based solely on a quick estimate, not on extensive research or calculations. Later in the lesson, they will have an opportunity to develop a general rule based on data provided.
After all students have completed the first page, conduct a brief discussion about their answers. However, do not judge or comment on their estimates. You may allow other students to offer comments, but you should only say that thinking about this estimate is a precursor to the activity that they will complete today. Then, divide the class into pairs or small groups; to half of these groups, distribute the sheet titled "Algebraic Approach," and to the other half of the groups, distribute the sheet titled "Geometric Approach." Allow the groups to work on their respective sheets, and then have groups with different sheets compare their results. They may be surprised by the results.
After students have completed the activity sheet, conduct a brief class discussion. Focus this discussion on the following questions:
- Using your formulas, determine how far a person standing at the top of Mount Everest would be able to see to the horizon. Compare the results generated by each formula.
- Consider a rocket 1000 miles (or 5,280,000 feet) above the Earth. Use both of your formulas to determine how far a person in this rocket would be able to see to the horizon. Do both formulas give the same result?
To conclude the lesson, allow students to explore the Distance to Horizon applet. This tool allows the user to adjust the height above sea level, and the distance to the horizon is calculated. The height can be adjusted to exactly 29,035 feet, the height of Mount Everest. At this height, the applet shows that the distance to the horizon is 208.8 miles. Students can use this value as a check of their results.
Selected Solutions to the Answer Sheet
Question 4. A power regression (accessible through the PwrReg feature on TI calculators) gives the function of best fit. The regression corresponds to the function d = 1.218 · h0.501. (This result is very similar to a formula used by ship captains who wished to estimate the distance to a shore. To calculate the distance to the horizon, they estimated the value of d = (1.5h)0.5.)
Questions 5 and 9. The power function above yields a result of 208.9 miles, whereas the formula that results from the geometric approach yields a result of 208.8 miles.
Question 7. The Pythagorean theorem can be used to generate an equation, but it must be remembered that the distance to the horizon is measured in miles, while the height above sea level is measured in feet. Consequently, a conversion needs to be done. Let n = h/5280, which is the height above sea level in miles. Then, the resulting equation is (3963 + n)2 = 39632 + d2.
Question 8. Solving for d then gives d = (7926n + n2)0.5.